(A) 230 m
(B) 240 m
(C) 260 m
(D) 320 m
(E) None of these
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(A) 230 m
(B) 240 m
(C) 260 m
(D) 320 m
(E) None of these
= 200 x (5 /18)m/sec
= 500/9 m/sec.
Let the length of the other train be x metres.
Then, (x + 270)/9 = 500/9
x + 270 = 500
x = 230.