1. Answer: Option (B) 10 a.m. Explanation: Suppose they meet x hours after 7 a.m. Distance covered by A in x hours = 20x km. Distance covered by B in (x - 1) hours = 25(x - 1) km. Therefore 20x + 25(x - 1) = 110 => 45x = 135 => x = 3. So, they meet at 10 a.m.

    Answer: Option (B) 10 a.m.
    Explanation:
    Suppose they meet x hours after 7 a.m.

    Distance covered by A in x hours = 20x km.

    Distance covered by B in (x – 1) hours = 25(x – 1) km.

    Therefore 20x + 25(x – 1) = 110

    => 45x = 135

    => x = 3.

    So, they meet at 10 a.m.

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  2. Answer: Option (A) 400 m Explanation: Let the length of the first train be x metres. Then, the length of the second train is x /2 metres. Relative speed = (48 + 42) kmph = 90 x (5/18) m/sec = 25 m/sec. Therefore [x + (x/2)]/25 = 12 or 3x/2 = 300 or x = 200. Therefore Length of first train = 200 m. LRead more

    Answer: Option (A) 400 m
    Explanation:
    Let the length of the first train be x metres.

    Then, the length of the second train is x /2 metres.
    Relative speed = (48 + 42) kmph = 90 x (5/18) m/sec = 25 m/sec.

    Therefore [x + (x/2)]/25 = 12 or 3x/2 = 300 or x = 200.

    Therefore Length of first train = 200 m.

    Let the length of platform be y metres.

    Speed of the first train = 48 x (5/18) ( m/sec = 40/3 m/sec.
    Therefore (200 + y) x( 3/40) = 45
    => 600 + 3y = 1800

    => y = 400 m.

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  3. Answer: Option (D) 81 km/hr Explanation: 4.5 km/hr = 4.5 x (5/18) m/sec = 5/4 m/sec = 1.25 m/sec, and 5.4 km/hr = 5.4 x (5/18)  m/sec = 3/2 m/sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) x 8.4 = (x - 1.5) x 8.5 => 8.4x - 10.5 = 8.5x - 12.75 => 0.1x = 2.25 => x =Read more

    Answer: Option (D) 81 km/hr
    Explanation:
    4.5 km/hr = 4.5 x (5/18) m/sec = 5/4 m/sec = 1.25 m/sec, and
    5.4 km/hr = 5.4 x (5/18)  m/sec = 3/2 m/sec = 1.5 m/sec.
    Let the speed of the train be x m/sec.

    Then, (x – 1.25) x 8.4 = (x – 1.5) x 8.5

    => 8.4x – 10.5 = 8.5x – 12.75

    => 0.1x = 2.25

    => x = 22.5

    Therefore Speed of the train = 22.5 x 18/5  km/hr = 81 km/hr.

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  4. Answer: Option (B) 50 m Explanation: 2 kmph = 2 x (5/18) ( m/sec = 5/9 m/sec. 4 kmph = 4 x (5/18) m/sec = 10/9 m/sec. Let the length of the train be x metres and its speed by y m/sec. Then,  x /(y-5/9) = 9 and  x/(y-10/9) = 10. Therefore 9y - 5 = x and 10(9y - 10) = 9x => 9y - x = 5 and 90y - 9xRead more

    Answer: Option (B) 50 m
    Explanation:
    2 kmph = 2 x (5/18) ( m/sec = 5/9 m/sec.
    4 kmph = 4 x (5/18) m/sec = 10/9 m/sec.
    Let the length of the train be x metres and its speed by y m/sec.

    Then,  x /(y-5/9) = 9 and  x/(y-10/9) = 10.

    Therefore 9y – 5 = x and 10(9y – 10) = 9x

    => 9y – x = 5 and 90y – 9x = 100.

    On solving, we get: x = 50.

    Therefore Length of the train is 50 m.

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  5. Answer: Option (C) 27(7/9) m Explanation: Relative speed = (40 - 20) km/hr =20 x (5/18) m/sec =  50/9 m/sec. Therefore Length of faster train = ( 50/9) x 5  m = 250/9 m = 27(7/9) m.

    Answer: Option (C) 27(7/9) m
    Explanation:
    Relative speed = (40 – 20) km/hr =20 x (5/18) m/sec =  50/9 m/sec.
    Therefore Length of faster train = ( 50/9) x 5  m = 250/9 m = 27(7/9) m.

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  6. Answer: Option (D) 82 km/hr Explanation: Let the speed of the second train be x km/hr. Relative speed = (x + 50) km/hr = (x + 50) x (5/18 )m/sec =  (250 + 5x)/18  m/sec. Distance covered = (108 + 112) = 220 m. Therefore 220/((250+5x)/18) = 6 => 250 + 5x = 660 => x = 82 km/hr.

    Answer: Option (D) 82 km/hr
    Explanation:
    Let the speed of the second train be x km/hr.

    Relative speed = (x + 50) km/hr
    = (x + 50) x (5/18 )m/sec
    =  (250 + 5x)/18  m/sec.

    Distance covered = (108 + 112) = 220 m.

    Therefore 220/((250+5x)/18) = 6
    => 250 + 5x = 660

    => x = 82 km/hr.

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  7. Answer: Option (B) 12 Explanation: Speed of the first train = 120/10 m/sec = 12 m/sec. Speed of the second train = 120/15  m/sec = 8 m/sec. Relative speed = (12 + 8) = 20 m/sec. Therefore Required time = (120 + 120)/20  sec = 12 sec.

    Answer: Option (B) 12
    Explanation:
    Speed of the first train = 120/10 m/sec = 12 m/sec.
    Speed of the second train = 120/15  m/sec = 8 m/sec.

    Relative speed = (12 + 8) = 20 m/sec.

    Therefore Required time = (120 + 120)/20  sec = 12 sec.

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  8. Answer: Option (C) 36 Explanation: Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 => 2x = 20 => x = 10. Therefore Speed of each train = 10 m/sec = 10 x (18/5) km/hr = 36 km/hr.

    Answer: Option (C) 36
    Explanation:
    Let the speed of each train be x m/sec.

    Then, relative speed of the two trains = 2x m/sec.

    So, 2x = (120 + 120)/12
    => 2x = 20

    => x = 10.

    Therefore Speed of each train = 10 m/sec = 10 x (18/5) km/hr = 36 km/hr.

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  9. Answer: Option (B) 24 sec Explanation: Relative speed = = (45 + 30) km/hr = 75 x 5 /18 m/sec =  125/6 m/sec. We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train. So, distance covered = Length of the slower train. Therefore, Distance coRead more

    Answer: Option (B) 24 sec
    Explanation:
    Relative speed = = (45 + 30) km/hr
    = 75 x 5 /18 m/sec
    =  125/6 m/sec.
    We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

    So, distance covered = Length of the slower train.

    Therefore, Distance covered = 500 m.

    Therefore Required time =  500 x (6/125) = 24 sec.

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  10. Answer: Option (B) 30 Explanation: Speed of the train relative to man = (63 - 3) km/hr = 60 km/hr =  60 x (5/18) m/sec =  50/3 m/sec. Therefore Time taken to pass the man =  500 x (3/50) sec = 30 sec.

    Answer: Option (B) 30
    Explanation:
    Speed of the train relative to man = (63 – 3) km/hr
    = 60 km/hr
    =  60 x (5/18) m/sec
    =  50/3 m/sec.
    Therefore Time taken to pass the man
    =  500 x (3/50) sec
    = 30 sec.

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