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Pankaj Chaudhary
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A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

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  1. Answer: Option (D) 79.2 km/hr
    Explanation:
    Let the length of the train be x metres and its speed by y m/sec.

    Then, x/y = 8 => x = 8y
    Now, (x + 264)/20 = y
    => 8y + 264 = 20y

    => y = 22.

    Therefore Speed = 22 m/sec = 22 x (18/5)  km/hr = 79.2 km/hr.

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