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Pankaj Chaudhary
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A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

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  1. Answer: Option (D) 82 km/hr
    Explanation:
    Let the speed of the second train be x km/hr.

    Relative speed = (x + 50) km/hr
    = (x + 50) x (5/18 )m/sec
    =  (250 + 5x)/18  m/sec.

    Distance covered = (108 + 112) = 220 m.

    Therefore 220/((250+5x)/18) = 6
    => 250 + 5x = 660

    => x = 82 km/hr.

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